c: make type of conditional expr with pointers match non void pointer

Here's what the C standard[1] says about the conditional operator:

```
if one operand is a null pointer constant, the result has the type of
the other operand; otherwise, one operand is a pointer to void or a
qualified version of void, in which case the result type is a
pointer to an appropriately qualified version of void.
``

But actually, some codebases rely on things like 'x ? &foo.memb : NULL'
to have the type of `&foo.memb`, and not `void *`...

[1]: ISO/IEC 9899:TC3 §6.5.15

1 files changed, 1 insertions, 1 deletions

diff --git a/src/c.c b/src/c.c
index 2d51bd2..c6df58f 100644
--- a/src/c.c
+++ b/src/c.c
@@ -540,7 +540,7 @@ condtype(const Expr *a, const Expr *b)
    if (t1.t == TYPTR && t2.t == TYPTR) {
       s1 = typechild(t1), s2 = typechild(t2);
       if (s1.bits == s2.bits || s2.t == TYVOID || s1.t == TYVOID) {
-         return mkptrtype(s1.t == TYVOID ? s1 : s2, (t1.flag | t2.flag) & TFCHLDQUAL);
+         return mkptrtype(s1.t == TYVOID ? s2 : s1, (t1.flag | t2.flag) & TFCHLDQUAL);
       }
    }
    return mktype(0);